Question is ⇒ Five cells are connected in series in a row and then four such rows are connected in parallel to feed the current to a resistive load of 1.25 ω. Each cell has an emf of 1.5 V with an internal resistance of 0.2 ω. The current through the load will be, Options are ⇒ (A) 3.33 A, (B) 23.33 A, (C) 5 A, (D) 1 A, (E) , Leave your comments or Download question paper.

Question is ⇒ Five cells are connected in series in a row and then four such rows are connected in parallel to feed the current to a resistive load of 1.25 ω. Each cell has an emf of 1.5 V with an internal resistance of 0.2 ω. The current through the load will be, Options are ⇒ (A) 3.33 A, (B) 23.33 A, (C) 5 A, (D) 1 A, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Five cells are connected in series in a row and then four such rows are connected in parallel to feed the current to a resistive load of 1.25 ω. Each cell has an emf of 1.5 V with an internal resistance of 0.2 ω. The current through the load will be
A.	3.33 A [Wrong Answer]
B.	23.33 A [Wrong Answer]
C.	5 A [Correct Answer]
D.	1 A [Wrong Answer]
View Answer 15 -12 Explanation:- Answer : C Discuss it below : Dhanya dhanu Said on 2020-03-17 03:49:41 V= nE = 51.5 = 7.5 volts Internal resistance of battary= 0.25/4=0.25ohm Load R =1.25 R total = 1.25+0.25=1.5 ohm I=V/R I= 5 amps Peter Assad Said on 2018-12-11 14:43:30 correct answer A n = 5, E = 1.5, R = 1.25, r = .2 where I = nE/(R+nr) = 3.33 A !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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