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Q1. | Find the electric charge required on the earth and moon to balance their gravitational attraction if the charge on the earth is 10 times that on the moon. |

A. | 1.73 TC [Wrong Answer] |

B. | 17.3 GC [Wrong Answer] |

C. | 17.3 TC [Correct Answer] |

D. | 1.73 GC [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒

*x*= AX + B

*u*is a state equation.

TRUE

FALSE

⇒ A lead compensator

speeds up the transient response

increases the stability margin

increases the stability margin and speeds up the transient-response.

none of the above.

⇒ In a lag network the input frequency is 100

*f*where

_{c}*f*is critical frequency. The voltage gain is

_{c}0 dB

-20 dB

-40 dB

-60 dB

⇒ A radio frequency choke permits an easy flow of __________ current and at the same time it offers a very impedance to __________ currents.

A.C., low frequency

A.C., high frequency

D.C., low frequency

D.C. high frequency

⇒ A NAND gate has 3 inputs and one output. The number of thyristors required for this gate are

1

2

3

3 or 4

⇒ A function is given

*f*(

*t*) = sin

^{2}

*t*+ cos

^{2}

*t*. Which of the following is true?

f has frequency components at 0 and 1/2p Hz

f has frequency components at 0 and 1/p Hz

f has frequency components at 1/2p and 1/p Hz

f has frequency components at 0, l/2p and 1/p Hz

⇒ The transfer function V

_{2}/V

_{1}for figure

a zero at origin

a zero at infinity

no zero

a zero at

*j*1

⇒ The most commonly used devices for differencing and amplification, in control systems, are

BJT amplifiers

FET amplifiers

operational amplifiers

either (a) or (b)

⇒ The name field effect is related to the __________ layers of a JFET.

depletion

drain

source

gate

⇒ Magnetic hysteresis phenomenon is explained by

motion of domain walls

motion of domain walls and domain rotation

domain rotation

none of the above

⇒ Which rectifier has the best ratio of rectification?

Half wave rectifier

Full wave rectifier

Bridge rectifier

Three phase full wave rectifier

⇒

**Assertion (A):** CMOS devices have very high speed.

**Reason (R):** CMOS devices have very small physical size and simple geometry.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is true, R is false

A is false, R is true

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Flash converter ADC | 1. | requires conversion time of a few μs |

B. | Dual slope ADC | 2. | requires DAC |

C. | Successive approximation ADC | 3. | minimizes the effect of power supply interference |

4. | requires complex hardware | ||

5. | is a tracking ADC |

A-2, B-3, C-4

A-4, B-3, C-2

A-5, B-4, C-3

A-1, B-2, C-5

⇒ The Depth of penetration of EM wave in medium having conductivity σ at a frequency of 1 MHz is 25 cm. The depth of penetration at a frequency of 4 MHz will be

6.25 cm

12.50 cm

50 cm

100 cm

⇒ In case of static storage elements

information is permanently stored

information is to be periodically refreshed

information is to be intermittently refreshed

information is lost in case power is removed

⇒ Consider the following statements a half adder.

- As a half subtractor also
- has two outputs C
_{H}=*x*x*y*and S_{n}=*x*⊕*y*for two inputs*x*and*y* - has two outputs CH =
*x*+*y*and SH =*x*⊕*y*for two inputs*x*and*y* - is a combinational circuit

1, 3, 4

1, 2, 4

4 only

2 and 3

⇒ The equivalent circuit of an op-amp has

a virtual ground at input

a virtual ground at output

virtual ground at input as well as at output

none of the above

⇒ The series element of a band stop filter is

capacitive

inductive

parallel combination of L and C

series combination of L and C

⇒ In figure V

_{011 Vi10 ViVi0}

⇒ The colour code on a carbon resistor is brown-black-red-gold. The value of resistance is

100 Ω

1000 Ω

1000 Ω ± 5%

1000 Ω ± 10%

⇒

**Assertion (A):** Moving iron instrument can be used on ac or dc.

**Reason (R):** In a moving iron instrument deflecting torque is proportional to square of current.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true R is false

A is false R is true

⇒ Schrodinger wave equation is a

linear equation

differential equation

partial differential equation

none of the above

⇒ In the given figure,

(A + B)C + DE

AB + C(D + E)

(A + B)C + D + E

none of the above

⇒ In the given figure shows a negative logic AND gate. If positive logic is used this gate is equivalen

AND gate

OR gate

NOR gate

NAND gate

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | h_{ie} | 1. | siemens |

B. | h_{oe} | 2. | no units |

C. | h_{fe} | 3. | ohms |

A-1, B-2, C-3

A-3, B-1, C-2

A-2, B-1, C-3

A-3, B-2, C-1

⇒ In using Nyquist stability criterion it is not necessary to determine closed loop poles.

TRUE

FALSE

⇒ If an electron move through a potential difference of 500 V, the energy possesses by it will be

500 ergs

500 joules

500 eV

500 mV

⇒

**Assertion (A):** Dielectric constant is independent of temperature unless the temperature is extremely high.

**Reason (R):** For normal temperatures the number of atoms per unit volume is constant.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true but R is false

A is false but R is true

⇒ An audio signal of FM radio station is sampled at a rate of 15% above the Nyquist rate. Signal is sampled in 512 levels and bandwidth of the signal is 4 KHz. The minimum bandwidth required to transmit this signal will be

77 K bits/sec

92 K bits/sec

84.8 K bits/sec

82.8 K bits/sec

⇒ The voltage applied to an R-L circuit at

*t*= 0 when switch is closed is 100 cos (100

*t*+ 30°). The circuit resistance is 80 Ω and inductance is 0.6 H (in which initial current is zero). What is the maximum amplitude of current flowing through the circuit?

0.0416666666666667

0.0833333333333333

0.208333333333333

0.416666666666667