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Q1. | Final value theorem is used to find |

A. | steady state value of system output [Correct Answer] |

B. | initial value of output [Wrong Answer] |

C. | transient beaviour of output [Wrong Answer] |

D. | none of these [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ An 8 level encoding scheme is used in a PCM system of 10

*k*H

*z*channel BW. The channel capacity is

80

*kbps*

60

*kbps*

30

*kbps*

18

*kbps*

⇒ An

*n*channel depletion type MOSFET has

lightly doped

*p*substrate and highly doped

*n*source and drain

highly doped

*p*substrate and highly doped

*n*source and drain

highly doped

*p*substrate and lightly doped

*n*source and drain

lightly doped

*n*substrate and highly doped

*n*source and drain

⇒ Consider the following statements

- A total of about 1 million bytes can be directly accessed by 8086 microprocessor.
- The 8086 has thirteen 16 bit registers.
- The 8086 has eight flags.
- Compared to 8086, the 80286 provides a higher degree of memory protection.

1, 2, 3, 4 are correct

1, 3, 4 are correct

1, 2, 4 are correct

1, 2, 3 are correct

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Fourier transform of a Gaussian function | 1. | Gaussian function |

B. | Convolution of a rectangular pulse with itself | 2. | Rectangular pulse |

C. | Current through inductor for step input voltage | 3. | Triangular pulse |

4. | Ramp function | ||

5. | Zero |

A-1, B-2, C-3

A-2, B-4, C-5

A-1, B-3, C-4

A-2, B-3, C-5

⇒ A practical Parallel resonant circuit has a coil in Parallel with a 0.14 μf capacitor. The coil has an inductance of 1 mH and a resistance of 10 ohms. The Q of the circuit is

1000

100

10

1

⇒ In the circuit shown below current through the resistor is shown. Voltage across 4 Ω resistor

8 volt

≈ 5.87 V

≈ 6.87 V

None of these

⇒ If damping ratio is 0.5, the lines joining complex poles with origin are inclined to negative real axis at

± 90°

± 60°

± 45°

± 30°

⇒ A two branch parallel tuned circuit has 100 Ω resistance and 0.1 H inductance in one branch and 10

^{-6}F capacitor in the other. At resonance frequency, the dynamic resistance is

10 Ω

100 Ω

1000 Ω

10000 Ω

⇒ Consider the following statements

- ECL has least propagation delay
- TTL has largest fan out
- CMOS has highest noise margin
- TTL has lowest power dissipation

1 and 3

2 and 4

3 and 4

1 and 2

⇒ The amplitude of a random signal uniformly distributed between - 5 V and 5 V. If the positive values of the signal are uniformly quantized with a step size of 0.05 V, and the negative values are uniformly quantized with a step size of 0.10 V, the resulting signal to quantization noise is approximately

46 dB

43.8 dB

42 dB

40 dB

⇒

**Assertion (A):** In a full wave rectifier output the lowest ac component is at twice the input frequency

**Reason (R):** In a full wave rectifier, the output waveform consists of half sinusoids

Both A and R are correct and R is correct explanation for A

Both A and R are correct but R is not correct explanation for A

A is correct R is wrong

A is wrong R is correct

⇒ Geosynchronous satellites are always launched in the equatorial plane because it is the only plane which provides

24-hour orbit

stationary satellite

global communication

zero-gravity environs

⇒ Above a certain temperature, the specific heat of a metal becomes constant. This temperature is called

Debye temperature

Curie temperature

Neel temperature

Transition temperature

⇒ The main function of a balanced modulator is to

produce balanced modulation of a carrier wave

produce 100% modulation

suppress carrier signal in order to create a single-sideband or double sideband

limit noise picked by a receiver

⇒ A full adder is to be implemented using half adders and OR gates. A 4 bit parallel adder without any initial carry requires

8 half adders and 4 OR gates

8 half adders and 3 OR gates

7 half adders and 3 OR gates

7 half adders and 4 OR gates

⇒ Bandwidth will be

*a*.

*b*

*a*+

*b*

*a*

*b*

⇒ A coil has a resistance of 2 Ω and inductance of 0.1 mH. The applied voltages is suddenly increased from 10 V to 20 V. After steady state condition have reached, the current is

0.0833333333333333

more than 2 A but less than 4 A

0.166666666666667

more than 4 A

⇒ An amplifier has input impedance of 4 kΩ and output impedance of 80 kΩ. It is used in negative feedback circuit with 10% feedback. If open loop gain is 90, the closed loop input and output impedances are

40 kΩ and 8 kΩ respectively

4 kΩ and 80 kΩ respectively

0.4 kΩ and 800 kΩ respectively

8 kΩ and 160 kΩ respectively

⇒ A D-flip-flop is

dial type flip-flop

delay flip-flop

differential flip-flop

digital flip-flop

⇒ The signal define by the equations

*u*(

*t*-

*a*) = 0 for

*t*<

*a*and

*u*(

*t*-

*a*) = 1 for

*t*≥

*a*is

a unit step function

a shifted unit step function orginating at

*t*=

*a*

a pulse function

none of the above

⇒ IC 7485 cannot be cascaded.

TRUE

FALSE

⇒ The resistance of a metallic wire would

increase as the operating frequency increase

decrease as the operating frequency increase

remain unaffected on increasing the operating frequency

first increase then decrease

⇒

**Assertion (A):** Impulse function is an important function in network analysis.

**Reason (R):** Convolution integral enables us to find the response of a network to an arbitary input in terms of the impulse response.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is true, R is false

A is false, R is true

⇒ The main advantage of using micro waves for communications is

large bandwidth

small bandwidth

low power

high power

⇒ What would be the rms value of a sine wave having the same peak value as that of the above mentioned periodic wave?

42.2 V

19 V

38.2 V

none

⇒ A two winding transformer is feeding a single phase half wave rectifier circuit. The load is purely resistive. The rms value of transformer secondary current is I

_{s}and rms value of load current in I

_{rms}. Then

I

_{s}= I

_{rms}irrespective of the value of firing angle

I

_{s}= 0.5 I

_{rms}irrespective of the value of firing angle

I

_{s}= I

_{rms}if firing angle is less than 30°

I

_{s}= I

_{rms}if firing angle is more than 30°

⇒ The A.C. resistance of the emitter diode will be

5.05 Ω

50.5 Ω

505 Ω

5050 Ω

⇒ An ac tachometer has a drag cup construction so that

rotor inertia is low

rotor body is conducting

rotor is easy to fabricate

both (a) and (b)

⇒ Which of the following instructions have only one operand?

Multiply

Add

Shift

Subtract

⇒ The difference between resonant commutation and self commutation is

both these methods are based on entirely different principles

in resonant commutation, the commutating elements carry load current but in self commutation, the commutating elements do not carry load current

resonant commutation uses L and C but self commutation uses only capacitor

none of the above