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Q1. | Father is aged three times more than his son Alok. After 8 years, he would be two and a half times of Alok's age. After further 8 years, how many times would he be of Alok's age? |

A. | 4 times [Wrong Answer] |

B. | 6 times [Wrong Answer] |

C. | 2 times [Correct Answer] |

D. | 3 times [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :Assume that Alok's present age = x. Then father's present age = 3x + x = 4x After 8 years, fathers age = 2 ½ times of Alok's age => (4x+8) = 2 ½ × (x+8) => 4x + 8 = (5/2) ×(x + 8) => 8x + 16 = 5x+ 40 => 3x = 40-16 = 24 => x = 24/3 = 8 After further 8 years, Alokl's age = x + 8+ 8 = 8+8+8 = 24 Father's age = 4x + 8 + 8 = 4 × 8 + 8 + 8 = 48 Father's age/Alok's age = 48/24 = 2 !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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