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Q1. | Eighteen years ago, a father was three times as old as his son. Now the father is only twice as old as his son. Then the sum of present ages of the son and father is: |

A. | 54 [Wrong Answer] |

B. | 72 [Wrong Answer] |

C. | 105 [Wrong Answer] |

D. | 108 [Correct Answer] |

View Answer
Explanation:-
Answer : DDiscuss it below :Let the present ages of the father and son be 2x and x years respectively.Then (2x-18)=3(x-18) => x=36 therefore, required sum=(2x+x)=3x=108 years !! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

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