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Q1. | Consider the following statemen |

A. | 1, 2, 3, 4 [Wrong Answer] |

B. | 1, 2, 3 [Correct Answer] |

C. | 1, 2 [Wrong Answer] |

D. | 1, 3, 4 [Wrong Answer] |

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Explanation:-
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**Also Read Similar Questions Below :**

⇒

**Assertion (A):** Damping in a vibration galvanometer is small.

**Reason (R):** Vibration galvanometer is a PMMC instrument.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true R is false

A is false R is true

⇒ In any two port network, input impedance is independent of load impedance.

TRUE

FALSE

⇒ A total of 16 equally probable events exist. If it is required to select one out of them, the number of required bits is

2

4

3

5

⇒ Assuming accumulator contain A 64 and the carry is set (1). What will register A and (CY) contain after ACI 0 A4 H?

4 AH, 0

4 AH, 1

4 BH, 0

4 BH, 1

⇒ A digital frequency counter can be converted to DVM by addition of a suitable

voltage controlled oscillator

D/A converter

power amplifier

operational amplifier

⇒ In the circuit of figure, the value of

*r*

_{e}is (neglecting

*v*

_{be100 Ω75 Ω50 Ω25 Ω}

⇒ If an amplifier with gain of - 1000 and feedback factor β = - 0.1 had a gain change of 20% due to temperature, the change in gain of the feedback amplifier would be

0.1

0.05

0.002

0.0001

⇒ The characteristic equation of flip-flop gives the next state Q

_{N + 1}in terms of present state Q

_{N}and the inputs. Which one of the following is the characteristic equation of J - K flip-flop?

Q

_{N+1}= JQ

_{N}+ KQ

_{N}

Q

_{N+1}= J + KQ

_{N}

Q

_{N+1}= KQ

_{N}+ JQ

_{N}

Q

_{N+1}= K + JQ

_{N}

⇒ For the logic circuit given, what is the simplified Boolean funct

X = AB + C

X = BC + A

X = AB + AC

X = AC + B

⇒ A semi converter operates in two quadrants.

TRUE

FALSE

⇒ A five bit binary adder is used to add 01001 and 00111. The adders from LSB position are numbered as FA

_{0}, FA

_{1}, FA

_{2}and FA

_{3}. The outputs of FA

_{2}are

SUM = 0

SUM = 0, CARRY = 1

SUM = 1, CARRY = 0

SUM = 1, CARRY = 1

⇒

**Assertion (A):** Operator has a value 1 ∠ - 90° or 1 ∠ 90°.

**Reason (R):** Operator '*a*' has a value 1 ∠ 120°.

Both A and R are true and R is correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true

⇒ Electrical conductivity of metals expressed in ohm

^{-1}m

^{-1}is of the order of

10

^{10}

10

^{5}

10

^{-4}

10

^{-6}

⇒ A network has only independent current sources and resistance. If values of all resistors are doubled, the values of node voltages

will become half

will remain unchanged

will become double

cannot be determined unless circuit configuration and values of resistors are known

⇒ A heater is rated at 230 V, 5 A AC. Then

both the current and voltage are peak values

both the current and voltage are rms values

the current is peak value and voltage is rms value

the current is rms value and voltage is peak value

⇒ A string of series connected thyristors needs equalising circuit to

ensure proper firing

ensure proper current division

ensure proper voltage division

none of the above

⇒ A rare gas has N atoms per m

^{3}. If electronic polarizability of single atom of this gas is a

_{e}, then

∈

_{r}= Na

_{e}

∈

_{0}∈

_{r}= Na

_{e}

∈

_{0}(∈

_{r}- 1) = Na

_{e}

∈

_{0}(∈

_{r}- 2) = Na

_{e}

⇒ Two voltages 50 V each have a phase difference of 45°. The rms value of resultant sum of the two voltages is

70.7 V

80.4 V

92.4 V

100 V

⇒ The property not valid for basic singularity function is

it is even signal

convolution of any arbitrary function x{t) and an impulse is the original function itself.

the sum of two impulses at same location is the impulse with the strength equal to the summation of individual strengths.

none of these.

⇒ In 8085, which of the following is an 8 bit register?

A

SP

PC

both (a) and (b)

⇒ A moving coil meter has a resistance of 50 ohms and a full scale deflection current of 20 mA. To convert it into a voltmeter of 0-100 V range, the series resistance should be

5000 Ω

5050 Ω

4950 Ω

505 Ω

⇒ The output

*Y*of the circuit shown in the figur

(A + B) C + DE

AB + C(D + E)

(A + B) C + D + E

(AB + C) . DE

⇒ In orthogonal BFSK, the energy of information bearing term is

the same as total transmitted energy

one-half of total transmitted energy

one-fourth of total transmitted energy

none of the above

⇒ In the following astable multivibrator circuit, which properties of

*v*

_{0}(

*t*) depends on R

_{2Only the frequencyOnly the amplitudeBoth the amplitudeNeither the amplitude nor the frequency}

⇒

Match the following:

List I (Operator) | List II (Description) | ||
---|---|---|---|

A. | ! = | 1. | Left shift |

B. | = = | 2. | Right Shift |

C. | < < | 3. | Equal to |

D. | > > | 4. | Not equal to |

A-1, B-2, C-3, D-4

A-2, B-3, C-4, D-1

A-4, B-1, C-3, D-2

A-4, B-3, C-1, D-2

⇒ The number of logic devices required in a Mod-16 synchronous counter are

4

5

6

7

⇒ For the system with given characteristic equat

3, 2, 0

4, 0, 1

3, 0, 2

4, 1, 0

⇒ The MOS symbol shown indicates that

- It is depletion type
- It is enhancement type
- It is channel
- It is P-channel
- Electrons flow from
*s*to D - Holes flow from D to
*s*

1, 3, 6

1, 3, 5

2, 4, 6

2, 3, 5

⇒ The frame of an electric motor is earthed through three earthing plates resistances 30 Ω, 20 Ω and 10 Ω respectively. During fault the energy dissipated by three plates are W

_{1}, W

_{2}and W

_{3}. Then

W

_{1}> W

_{2}> W

_{3}

W

_{1}< W

_{2}< W

_{3}

W

_{1}= W

_{2}= W

_{3}

W

_{1}+ W

_{3}< W

_{2}

⇒

**Assertion (A):** The number of basic loops is equal to number of links.

**Reason (R):** The graph theory helps in choosing independent variables in circuit analysis.

Both A and R are true and R is correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true