Question is ⇒ Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is whit with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yk represent the random variable y(tk</, Options are ⇒ (A) 1010, (B) 107, (C) 1.414 x 10-10, (D) 2 x 10-20, (E) , Leave your comments or Download question paper.

Question is ⇒ Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is whit with power spectral density SN(f) = N0/2 = 10-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Yk represent the random variable y(tk</, Options are ⇒ (A) 1010, (B) 107, (C) 1.414 x 10-10, (D) 2 x 10-20, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	Consider a baseband binary PAM receiver shown below. The additive channel noise n(t) is whit with power spectral density S_N(f) = N₀/2 = 10^-20 W/Hz. The low-pass filter is ideal with unity gain and cutoff frequency 1 MHz. Let Y_k represent the random variable y(t_k
A.	10¹⁰ [Wrong Answer]
B.	10⁷ [Correct Answer]
C.	1.414 x 10^-10 [Wrong Answer]
D.	2 x 10^-20 [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ The range of a cordless telephone is about
1000 m
500 m
100 m
10 m

⇒ The behaviour of a JFET is similar to that of
NPN transistor
PNP transistor
SCR
Vacuum triode

⇒ When a current flows through a coil of insulated wire, the coil shows the properties of a magnet.
TRUE
FALSE

⇒ Decimal 43 in hexadecimal and BCD number system is respectively.
B2, 01000011
2B, 01000011
2B, 00110100
B2, 01000100

⇒ A fully charged mobile phone with a 12 V battery is good for a 20 minute talktime. Assume that, during the talk time, the battery delivers a constant current of 2 A and its voltage drops linearly from 12 V to 10 V as shown in the figure. How much energy does the battery deliver during this talk t
220 J
12 kJ
13.2 kJ
14.4 kJ

⇒ If operator 'a' = 1 ∠120° then (1 - a²) =
1 ∠ - 30°
1 ∠ 30°
1 ∠ - 60°
1 ∠60°

⇒

Assertion (A): A high dv/dt may cause triggering of a thyristor.

Reason (R): A high dv/dt results in charging current in the thyristor.

Both A and R are correct and R is correct explanation of A
Both A and R correct but R is not correct explanation of A
A is correct but R is wrong
A is wrong but R is correct

⇒

Assertion (A): A half cycle of sine wave can be expressed as sum of sine wave and another sine wave shifted by T/2 where T is the time period.

Reason (R): The function u(t - t₀) - u(t - t₀ - T) is a gate function occuring at t = t₀ and of duration T.

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is true, R is false
A is false, R is true

⇒ The total inductance of two coils is 60 mH in series aiding connection and 40 mH in series opposing connection. The mutual inductance between coils is
20 mH
10 mH
5 mH
2.5 mH

⇒ Efficiency of a half wave diode rectifier is less than 40%.
TRUE
FALSE

⇒ The ratio of diffusion constant for hole D_P to the mobility for holes is proportional to
T²
T
1/T
T³

⇒ Double integration of unit step function leads to
an impulse
a parabola
a ramp
a doublet

⇒ For a Mod-64 synchronous counter the number of flip flops and AND gates needed is
6 and 4 respectively
4 and 6 respectively
7 and 5 respectively
5 and 7 respectively

⇒ A counter type A/D converter contains a 4 bit binary ladder and a counter driven by a 2 MHz clock. Then conversion time
8 μ sec
10 μ sec
2 μ sec
5 μ sec

⇒ In the circuit of figure, the source supplies, 2.25 mA. The value of R mus
5 Ω
3 Ω
1.5 Ω
0.5 Ω

⇒ For a level input sequential circuit
output in a level only
output is in the pulse form
output may be a pulse or a level form
none of these

⇒ PAL stands for
Phase Attenuation by Line
Phase Alternation by Line
Parabolic Alternation by Line
Picture Alternation by Line

⇒ Epitaxial growth is used in IC_s
because it produces low parasitic capacitance
because it yields back to back isolating pn Junction
to grow single crystal n doped silicon on a single crystal P-type substrate
to grow Selectivity single crystal P doped silicon of one resistivity on a P type substrate of a different resistivity

⇒ The most widely used LC oscillator is
Hartley oscillator
Crystal oscillator
Colpitt's oscillator
Clapp's oscillator

⇒ Accumulator is an 8 bit register and is also known as register B.
TRUE
FALSE

⇒ The intrinsic impedance of free space
increases with increase of frequency
decreases with increase of frequency
is independent of frequency
none

⇒ Frequency range for satellite communication is
1 kHz to 100 kHz
100 kHz to 10 MHz
10 MHz to 100 MHz
1 GHz to 30 GHz

⇒ The numerical value of directivity of current element of half-wave dipole is 1.76 and 2.15 dB respectively. The directive gain of half-wave dipole over current element will be
3.91 dB
1.95 dB
0.39 dB
0.195 dB

⇒ Examine the following truth table. The product of sum from this truth tabl
(X + Y) (X + Y)
(X + Y) (X + Y)
(X + Y) (X + Y)
(X + Y) (X + Y)

⇒ In the circuit, the value of the voltage source
-22 V
-12 V
+12 V
-10 V

⇒ In 8085 microprocessor, even after a Reset operation which of the following interrupts remains enabled?
INTR
RST 5.5
RST 7.5
TRAP

⇒ In figure, the switch is closed at t = 0 when current through inductor is 6 A, the rate of change of current through resistor is 6 A/s. The value of
1 H
2 H
3 H
4 H

⇒ The MOS symbol shown indicates that

It is depletion type
It is enhancement type
It is channel
It is P-channel
Electrons flow from s to D
Holes flow from D to s

The true statements
1, 3, 6
1, 3, 5
2, 4, 6
2, 3, 5

⇒ An RC impedance function has a constant value at s = 0. The last element in the first cauer synthesis
will be a capacitor
may be R or C
will be R
will depend on the behaviour of function at s = ∞

⇒ In figure, the capacitor is charged to 1 V. At t = 0 the switch is closed so that i = e^-t. When i = 0.37 A, the voltage across capacito
1 V
0.63 V
0.37 V
0.185 V