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Q1. | Breakdown in dielectric may be |

A. | electrical breakdown [Wrong Answer] |

B. | thermal breakdown [Wrong Answer] |

C. | electrochemical breakdown [Wrong Answer] |

D. | any of the above [Correct Answer] |

View Answer
Explanation:-
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**Also Read Similar Questions Below :**

⇒ An input voltage V(

*t*) = 10 2 cos (

*t*+ 10°) + 10 3 cos (2

*t*+ 10°)

*V*is applied to a series combination of resistance R = 1 kΩ inductance L = 1H. The resulting steady-state current

*i*(

*t*) in ampere is

10 cos (

*t*+ 55°) + 10 cos (2

*t*+ 10° tan

^{-1}2)

10 cos (

*t*+ 55°) + 103/2 cos (2

*t*+ 55°)

10 cos (

*t*- 35) + 10 cos (2

*t*+ 10° - tan

^{-1}2)

10 cos (

*t*- 35) + 103/2 cos (2

*t*+ 35°)

⇒ A

*Q*meter uses the principle of

variation of self inductance

variation of mutual inductance

series resonance

none of the above

⇒ At frequencies of 10 MHz and higher the impedance represented by ground is primarity

resistive

inductive

capacitive

partly resistive and partly capacitive

⇒ A lossless transmission line with air dielectric is 6 m long. What is the line length at 30 MHz?

1 wavelength long

0.5 wavelength long

0.6 wavelength long

0.25 wavelength long

⇒ Silicon and germanium have diamond structure. The number of atoms in a volume equal to

*a*

^{3}where

*a*is the edge of elementary cube are

32

16

8

4

⇒ In the given figure forward current wave has a magnitud

0.45 A

0.3 A

0.2 A

0.1 A

⇒ In a current transformers

the number of turns in primary and secondary windings are nearly equal

the number of primary turns is very small as compared to number of secondary turns.

the number of secondary turns is very small as compared to the number of primary turns

either (a) or (c).

⇒ Which one of the following is correct? Energy of a power signal is

finite

zero

infinite

between 1 and 2

⇒ For a transmission line open circuit and short circuit impedances are 20 Ω and 5 Ω. Then characteristic impedance is

100 Ω

50 Ω

25 Ω

10 Ω

⇒ Dielectric constant and conductivity of rocky soil and flat sandy soil are around

10 and 20 mho/cm respectively

20 and 10 mho/cm respectively

2 and 5 mho/cm respectively

0.5 and 2 mho/cm respectively

⇒ In a junction transistor, the collector cut-off current 'I

_{CB0}' reduces considerably by doping the

emitter with high level of impurity

emitter with low level of impurity

collector with high level of impurity

collector with low level of impurity

⇒ In the circuit shown, the steady state is reached with S open S is closed at

*t*= 0, the current I in the 1 Ω resistor connected is to be determined at

*t*= 0

^{+}is give

1

2

3

42828

⇒ Modified Mc Murray full bridge inverter uses

4 thyristors and 2 diodes

4 thyristors and 4 diodes

8 thyristors and 4 diodes

8 thyristors and 8 diodes

⇒ A CT is used to feed current coils of wattmeter, energy meter, power factor meter and an ammeter. Then

all the coils are in series

all coils are in parallel

the coils are in series-parallel

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⇒ In an R-C circuit, the impedance is 40 Ω at a frequency of 100 Hz. At 200 Hz the impedance should be

40 Ω

80 Ω

20 Ω

more than 20 Ω but less than 40 Ω

⇒ In p mode of operation of magnetron the spikes due to phase focussing effect rotate at an angular velocity corresponding to

one pole/cycle

two pole/cycle

four pole/cycle

six pole/cycle

⇒ A voltage wave

*v*= 10 + 20 sin ω

*t*+ 7.5 sin 3 ω(

*t*) is applied to a series combination of two elements. The current is

*i*= 5 sin (ω

*t*+ 20°) + 1.5 sin (3ω

*t*+ 10°). The elements are

R and C

R and L

L and C

both inductances

⇒

**Assertion (A):** XOR gate is not universal gate.

**Reason (R):** It is not possible to realize any Boolean function using XOR gates only.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is true, R is false

A is false, R is true

⇒ In a 100% amplitude modulated signal, the power in the upper sideband when carrier power is to be 100 W and modulation system SSBSC, is

100 W

66 W

50 W

25 W

⇒ In which mode of BJT operation are both junctions forward biased?

Active

Saturation

Cut off

Reverse active

⇒ A variable reluctance tachometer has 180 teeth on rotor. The speed of shaft on which it is mounted in 1200 rpm. The frequency of output pulses is

1800 per second

3600 per second

4800 per second

5600 per second

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | Wein bridge oscillator | 1. | Low output impedance |

B. | Voltage shunt feedback amplifier | 2. | RF frequency range |

C. | Crystal oscillator | 3. | Audio frequency range |

D. | Current shunt feedback amplifier | 4. | High input impedance |

5. | High output impedance |

A-3, B-1, C-2, D-5

A-3, B-5, C-1, D-2

A-4, B-3, C-1, D-2

A-5, B-1, C-2, D-1

⇒ A 3 kV circuit uses SCR of 800 V rating. If derating is 25%, the number of SCRs in series is

4

5

6

8

⇒

`ALU 1C 74181`

can accept two words each having2 bits

4 bits

8 bits

16 bits

⇒ The function Y = AC + BD + EF is

POS

SOP

Hybrid

none of the above

⇒ In a 3 phase full wave regulator feeding a star connected resistance load the input voltage is 400 V line to line. The firing angle is 160°. The line to line output voltage would be

400 V

about 100 V

about 20 V

zero

⇒ As compared to a

*p*-

*n*junction diode

a schottky diode has lower cut in voltage and lower reverse saturation current

a schottky diode has higher cut in voltage and higher reverse saturation current

a Schottky diode has lower cut in voltage and higher reverse saturation current

a schottky diode has higher cut in voltage and lower reverse saturation current

⇒ The waveguides compared to equivalent transmission lines at low frequency are

able to carry more power

less noisy

having lower attenuation

all of the above

⇒ If the energy gap of a semiconductor is 1.1 eV, then it would be

opaque to visible light

transparent to visible light

transparent to ultraviolet radiation

transparent to infrared radiation

⇒ Which of the following statements is true regarding the fundamental mode of the metallic waveguides sh

Only P has no cutoff- frequency

Only Q has no cutoff- frequency

Only P has no cutoff- frequency

All there have cut-off frequency