Question is ⇒ An input voltage V(t) = 10 2 cos (t + 10°) + 10 3 cos (2t + 10°)V is applied to a series combination of resistance R = 1 kΩ inductance L = 1H. The resulting steady-state current i(t) in ampere is, Options are ⇒ (A) 10 cos (t + 55°) + 10 cos (2t + 10° tan-12), (B) 10 cos (t + 55°) + 103/2 cos (2t + 55°), (C) 10 cos (t - 35) + 10 cos (2t + 10° - tan-12), (D) 10 cos (t - 35) + 103/2 cos (2t + 35°), (E) , Leave your comments or Download question paper.

Question is ⇒ An input voltage V(t) = 10 2 cos (t + 10°) + 10 3 cos (2t + 10°)V is applied to a series combination of resistance R = 1 kΩ inductance L = 1H. The resulting steady-state current i(t) in ampere is, Options are ⇒ (A) 10 cos (t + 55°) + 10 cos (2t + 10° tan-12), (B) 10 cos (t + 55°) + 103/2 cos (2t + 55°), (C) 10 cos (t - 35) + 10 cos (2t + 10° - tan-12), (D) 10 cos (t - 35) + 103/2 cos (2t + 35°), (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	An input voltage V(t) = 10 2 cos (t + 10°) + 10 3 cos (2t + 10°)V is applied to a series combination of resistance R = 1 kΩ inductance L = 1H. The resulting steady-state current i(t) in ampere is
A.	10 cos (t + 55°) + 10 cos (2t + 10° tan^-12) [Wrong Answer]
B.	10 cos (t + 55°) + 103/2 cos (2t + 55°) [Wrong Answer]
C.	10 cos (t - 35) + 10 cos (2t + 10° - tan^-12) [Correct Answer]
D.	10 cos (t - 35) + 103/2 cos (2t + 35°) [Wrong Answer]
View Answer 2 -4 Explanation:- Answer : C Discuss it below : Pankaj Jareda Said on 2020-10-05 05:15:13 Give the solution.... !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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