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An enzyme has a Km of 4.7 x 10-5M. If the Vmax of the preparation is 22m moles liter-1 min-1, what velocity would be observed in the presence of 2.0 x 10-4M substrate and 5.0 x 10-5M of a competitive inhibitor? | |
A. | 13.54μ moles liter-1min-1 [Correct Answer] |
B. | 6.68μ moles liter-1min-1 [Wrong Answer] |
C. | 7.57μ moles liter-1min-1 [Wrong Answer] |
D. | 17.8μ moles liter-1min-1 [Wrong Answer] |