Question is ⇒ A voltage v = 100 sin (100 pt + 45°) V is applied to an impedance 10 + j10 ohm. The current is, Options are ⇒ (A) 10 ∠45° A, (B) 7.07 ∠45° A, (C) 5 ∠45° A, (D) 5 ∠0 A, (E) , Leave your comments or Download question paper.

Question is ⇒ A voltage v = 100 sin (100 pt + 45°) V is applied to an impedance 10 + j10 ohm. The current is, Options are ⇒ (A) 10 ∠45° A, (B) 7.07 ∠45° A, (C) 5 ∠45° A, (D) 5 ∠0 A, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	A voltage v = 100 sin (100 pt + 45°) V is applied to an impedance 10 + j10 ohm. The current is
A.	10 ∠45° A [Wrong Answer]
B.	7.07 ∠45° A [Wrong Answer]
C.	5 ∠45° A [Wrong Answer]
D.	5 ∠0 A [Correct Answer]
View Answer 1 -1 Explanation:- Answer : D Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

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