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A voltage v = 100 sin (100 pt + 45°) V is applied to an impedance 10 + j10 ohm. The current is | |
A. | 10 ∠45° A [Wrong Answer] |
B. | 7.07 ∠45° A [Wrong Answer] |
C. | 5 ∠45° A [Wrong Answer] |
D. | 5 ∠0 A [Correct Answer] |
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