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Q1. | A Varactor diode has |

A. | a fixed capacitance [Wrong Answer] |

B. | a fixed inductance [Wrong Answer] |

C. | a voltage variable capacitance [Correct Answer] |

D. | a current variable inductance [Wrong Answer] |

View Answer
Explanation:-
Answer : CDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ In metals, the flow of current is due to

electrons

ions

holes

electrons and ions

⇒ If

*x*

_{1}(

*t*) = 2 sin p

*t*+ cos 4 p

*t*and

*x*

_{2}(

*t*) = sin 5 p

*t*+ 3 sin 13 p

*t*then

*x*

_{1},

*x*

_{2}both periodic

*x*

_{1}

*x*

_{2}both not periodic

*x*

_{1}periodic,

*x*

_{2}not periodic

*x*

_{1}is not periodic ; but

*x*

_{2}is periodic

⇒

**Assertion (A):** The impedance of a matched load is equal to characteristic impedance of line.

**Reason (R):** A matched termination absorbs all the power incident on it.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct but R is wrong

A is wrong but R is correct

⇒ ALU carries out

arithmetic operations

logic operations

both arithmetic and logic operations

none of the above

⇒ The input gate current of FET is closer to

few amperes

few milli amperes

few microamperes

negligibly smaller value

⇒ To ensure that only dominant TE

_{10}mode propagates in a rectangular waveguide, the operating frequency

must be more than cutoff frequency of

*TE*

_{10}mode

must be less than cutoff frequency of

*TE*

_{20}mode

must be more than cutoff frequency of

*TE*

_{10}mode and less than cutoff frequency of TE

_{20}mode

must be less than cutoff frequency of

*TE*

_{10}mode

⇒ FSK is a system involving

pulse modulation

frequency modulation

amplitude modulation

phase modulation

⇒ Which DOS command improves memory usage?

MEM MAKER

MOVE

MEM IM

None on the above

⇒ Evaluate the value of 2 [

*u*(

*t*- 1) -

*u*(1 - 2

*t*)] (

*u*(

*t*+ 1) +

*u*(

*t*)) at

*t*= 3 sec.

0

4

∞

1

⇒ Energy density function is always

even

odd

neither even nor odd

both (a) and (b)

⇒ In an ac network the sum of currents entering a node is 10 ∠45°. The sum of currents leaving the node is

19.32 ∠45°

15 ∠45°

20 ∠45°

zero

⇒ The compensator of the given figure

lag compensator

lead compensator

lag-lead compensator

none of the above

⇒ Linear transistor circuits always operate in

saturation region

cut off region

active region

passive region

⇒

Match the following:

List I (Component) | List II (Dominant TE mode) | ||
---|---|---|---|

A. | Rectangular wave guide | 1. | TE_{101} |

B. | Circular waveguide | 2. | TE_{10} |

C. | Rectangular cavity | 3. | TE_{111} |

4. | TE_{11} |

A-4, B-2, C-1

A-2, B-1, C-3

A-3, B-4, C-1

A-2, B-3, C-1

⇒ The minimum step size required for a Delta modulator operating at 36 samples/sec to track the signal (here

*u*(

*t*) is the unit step function)

*x*(

*t*) = 125

*t*(

*u*(

*t*) -

*u*(

*t*- 1)) + (250 - 125

*t*) (

*u*(

*t*- 1) -

*u*(

*t*- 2)) So that slope overload is avoided, would be

2

^{-10}

2

^{-8}

2

^{-6}

2

^{-4}

⇒ An ideal op-amp has

infinite input and output resistance

low input and output resistance

low input and high output resistance

infinite input resistance and zero output resistance

⇒ The fluctuation in the received signal strength at the receiver of a random variation in the received signal is known as

fluctuation

fading

absorption

cycling

⇒ In Fermi-Dirac statistics, the probability of electron occupation of an energy level equal to Fermi level is

0

0.25

0.5

1

⇒ In the graph shown in the figure, for the tree with branches

*b*,

*d*and

*f*the fundamental loops would inclu

*abf, def, bdea*

*bdc, def, fba*

*abde, def, cdb*

*cea, bdea, abbf*

⇒ The initial contents of the 4 bit serial in parallel out right shift, shift register shown in figure is 0110. After three clock pulses are applied, the contents of the shift register wil

0

101

1010

1111

⇒ In a radio receiver with simple AGC

the highest AGC voltage is produced between stations

an increase in signal strength produces more AGC

the audio stage gain is normally controlled by AGC

the faster the time constant of AGC, more accurate the output

⇒ Which of the following terminations makes the input impedance of a line equal to characteristic impedance Z

_{0}?

line open circuited at far end

line terminated in Z

_{0}

line short circuited at far end

line terminated in inductance

⇒ The maximum distance between television transmission and receiving antennas for reasonably good reception should be

less than 20 km

less than 100 km

less than 500 km

less than 1000 km

⇒ The relation between thermal conductivity K (W/m/°C), heat flow density Q (watt/m

^{2}) and

*d*T/

*dx*(°C per metre) is

Q = K(

*d*T/

*dx*)

Q = - K(

*d*T/

*dx*)

K = Q(

*d*T/

*dx*)

*d*T/

*dx*= - QK

⇒ In Quine-Mclusky method of Boolean function reduction; __________ , are treated as __________ and therefore discrepancies may occur in the final solution, therefore this method is not applicable to the functions with __________ .

zeros, don't care conditions, zeros

one's, don't care conditions, one's

don't care conditions, zeros, don't care conditions

don't care conditions, don't care conditions, don't care conditions

⇒ The number of comparator circuits required to build a three-bit simultaneous A/D converter is

7

8

15

16

⇒ The portion of the atmosphere closest to ground is called ionosphere.

TRUE

FALSE

⇒ The decimal equivalent of ABC

_{16}is

348

2583

2748

33

⇒ Johnson noise is

white for all Practical application

always white

depends on temperature

never white

⇒ For a full wave bridge rectifier supplied with 50 Hz a.c., the lowest ripple frequency will be

50 Hz

100 Hz

200 Hz

400 Hz