Question is ⇒ A signal with ± 10 V ranged and 1 KHz band width is being digitized using a sample and hold circuit and a 10 bit quantizer. The quantization step is :, Options are ⇒ (A) 1 x 10-9 V, (B) 5 x 10-9 V, (C) 2.5 x 10-9 V, (D) 0.5 x 10-9 V, (E) , Leave your comments or Download question paper.

Question is ⇒ A signal with ± 10 V ranged and 1 KHz band width is being digitized using a sample and hold circuit and a 10 bit quantizer. The quantization step is :, Options are ⇒ (A) 1 x 10-9 V, (B) 5 x 10-9 V, (C) 2.5 x 10-9 V, (D) 0.5 x 10-9 V, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	A signal with ± 10 V ranged and 1 KHz band width is being digitized using a sample and hold circuit and a 10 bit quantizer. The quantization step is :
A.	1 x 10^-9 V [Wrong Answer]
B.	5 x 10^-9 V [Wrong Answer]
C.	2.5 x 10^-9 V [Wrong Answer]
D.	0.5 x 10^-9 V [Correct Answer]
View Answer 1 -2 Explanation:- Answer : D Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ In high power AM transmission modulation is done at
IF stage
RF power
buffer stage
oscillator stage

⇒ When a CE transistor is cut off
voltage across collector reduces to zero
voltage across collector is maximum
maximum collector current flows
maximum voltage appears across the load resistance

⇒ Given that the band gap of cadmium sulphide is 2.5 eV, the maximum photon wavelength, for e^--hole pair generation will be
5400 mm
540 mm
5400 Å
540 Å

⇒ The overall noise temperature T_e, absolute temperature T and noise figure F are related as
T_e = T(F - 1)
T_e = F(T - 1)
T = T_e(F - 1)
T_e = (T)(F)

⇒ A function of one of more variables which conveys information on the nature of physical phenomenon is called
Noise
Interference
System
Signal

⇒

Assertion (A): If an electron having charge e is revolving in an orbit of radius R and with angular velocity ω, the magnetic dipole moment of orbit is 0.5 eωR².

Reason (R): Orbital angular momentum and magnetic dipole moment are always equal.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not correct explanation of A
A is true but R is false
A is false but R is true

⇒ Capacitance hats are installed on low frequency antenna is
increase the electrical length
reduce the electrical length
protect against lightening
protect against corona effects

⇒ Short circuited stubs are preferred to O.C stubs because
O.C stubs are incapable of giving full range of reactances
O.C stubs are liable to radiate
O.C stubs are difficult to make and connect
none of the above

⇒ A transmission line is feeding 1 watt of power to a horn antenna having a gain of 10 dB. The antenna is matched to the transmission line. The total power radiated by the horn antenna into the free space is
10 watts
1 watt
0.1 watt
0.01 watt

⇒ A machine cycle has one clock cycle.
TRUE
FALSE

⇒ In 8085, the pins for SID and SOD are
4 and 5 respectively
5 and 4 respectively
3 and 4 respectively
4 and 3 respectively

⇒ A system with transfer function H(z) has impulse response h(.) defined as h(2) = 1, h(3) = -1 and h(k) = 0 otherwise. Consider the following statem
Only S2 is true
Both S1 and S2 are false
Both S1 and S2 are true, and S2 is a reason for S1
Both S1 and S2 are true, but S2 is not a reason for S1

⇒ In a JFET
gate source cut off voltage is equal to V_DS
gate source cut off voltage is equal to pinch off voltage
gate source cut off voltage is twice the pinch off voltage
gate source cut off voltage is equal to negative pinch off voltage

⇒

Match the following:

	List I		List II
A.	C	1.	7 eV
B.	Si	2.	1.15 eV
C.	Ge	3.	0.75 eV
D.	Sn	4.	0.1 eV
E.	Pb	5.	0 eV

A-2, B-3, C-4, D-5, E-1
A-1, B-2, C-3, D-4, E-5
A-3, B-1, C-2, D-5, E-4
A-4, B-5, C-1, D-2, E-3

⇒ Double integration of unit step function leads to
an impulse
a parabola
a ramp
a doublet

⇒ In JK flip flop toggle state exists if
J = 0, K = 1
J = 1, K = 0
J = 0, K = 0
J = 1, K = 1

⇒ In FM,
there is a large decrease in noise and hence increase in the signal to noise ratio
there is a large increase in noise and hence decrease in the signal to noise ratio
there is a large increase in noise and hence increase in the signal to noise ratio
there is a large decrease in noise and hence decrease in the signal to noise ratio

⇒ The input to a coherent detector is DSB - SC signal plus noise. The noise at the detector output is
in phase component
quadrature component
zero
the envelope

⇒ Two currents have the same peak value. Wave 1 is sinusoidal and wave 2 is rectangular. The ratio of their heating effects are
0.0423611111111111
1 : 2
0.0430555555555556
0.000711805555555555

⇒ In Bode plots the frequency at which two asymptotes meet is called corner frequency.
TRUE
FALSE

⇒ The phase velocity in a coaxial line is
greater than C
equal to C
less than C
not depend on C

⇒ Three identical coils each having self inductance L are connected in series so that the fluxes of all the three are in the same direction. If mutual inductance between each pair of coils is M, the total inductance of the arrangement is
3 L + 9 M
1.5 L + 3 M
3 L + 3 M
3 L + 6 M

⇒ In figure, a voltmeter of internal resistance 1200 Ω is connected across 600 Ω resistance and it reads 5 V. The value of
1200 Ω
2400 Ω
3600 Ω
7200 Ω

⇒ A transmission line has a characteristic impedance of 50 Ω and a resistance of 0.1 Ω/m, if the line is distortion less, the attenuation constant (in Np/m) is
500
5
0.014
0.002

⇒ In a JFET, gates are always
forward biased
reverse biased
either forward or reverse biased
unbiased

⇒ A loss less line is terminated in a circular lines are E lines
SWR = 0
SWE = 0
SWR is finite
SWR = ∞

⇒ In calculating input impedance, the load impedance is considered to be connected at the output.
TRUE
FALSE

⇒ The output y(t) of a linear time invariant system is related to its input x(t) by the following equation y(t) = 0.5x(t - t_d + 1) + x(t - t_d) + 0.5 x(t - t_d + 7). The filter transfer function H(ω) of such a system is given by
(1 + cos ωt)e^-jωt d
(1 + 0.5 cos ωt)e^-jωt d
(1 + cos ωt)e^jωt d
(1 - 0.5 cos ωt)e^-jωt d

⇒ The pole-zero plot given below corresponds
low pass filter
high pass filter
band pass filter
notch filter

⇒ A full wave rectifier circuit using centre tapped transformer and a bridge rectifier are fed at 100 V, 50 Hz. The frequencies of outputs in these two rectifiers are
100 Hz each
50 Hz each
100 Hz and 50 Hz
50 Hz and 100 Hz