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Q1. | A power supply has full-load voltage of 20 V. What will be its no load voltage when its voltage regulation is 100% |

A. | 0 V [Wrong Answer] |

B. | 10 V [Wrong Answer] |

C. | 20 V [Wrong Answer] |

D. | 40 V [Correct Answer] |

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Explanation:-
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**Also Read Similar Questions Below :**

⇒

Match the following:

List I (Octal) | List II (Decimal number) | ||
---|---|---|---|

A. | 35 | 1. | 53 |

B. | 65 | 2. | 62 |

C. | 54 | 3. | 29 |

D. | 76 | 4. | 44 |

A-4, B-3, C-2, D-1

A-1, B-2, C-3, D-4

A-2, B-3, C-1, D-4

A-3, B-1, C-4, D-2

⇒ The tape recorders used in homes have

common head and common amplifier system for recording and playback

different heads and amplifiers for recording and playback

same head but different amplifiers for recording and playback

different heads but same amplifier for recording and playback

⇒ In following figure find V

_{DSQ}by assuming gate current is negligible for the

*p*-channel JFET. (if I

_{DQ}= - 6 mA, R

_{S}= 0, V

_{DD}= -18 V, R

_{D}= 2 kΩ, I

_{DSS}= - 10 mA, I

_{PO}= - 3 V)

4 V

- 6 V

- 10 V

6 V

⇒ Dielectric strength of which of the following material has the highest dielectric strength?

Porcelain

Soft rubber

Glass

Joule effect

⇒ In figure, V

_{EB}= 0.6 V, β = 99. Then V

_{C}and I

_{C}

9.3 V and 1.98 mA respectively

4.6 V and 1.98 mA respectively

9.3 V and 0.02 mA respectively

4.6 V and 0.02 mA respectively

⇒ A two branch parallel tuned circuit has a coil of resistance 100 Ω and inductance 0.005 H in one branch and 10

*n*F capacitor in the second branch. At resonance frequency, the dynamic resistance is

1 Ω

10 Ω

100 Ω

more than 100 Ω

⇒ An FM signal with deviation δ is passed through mixer. Its frequency is reduced five fold. The deviation in output of mixer is

0.28

δ

5 δ

very very high

⇒

**Assertion (A):** For most metals, Fermi energy E_{F} is less than 10 eV.

**Reason (R):** Fermi level of a metal is given by E_{F} = 3.64 x 10^{-19} (*n*)^{2/3} where *n* is number of free electrons/m^{3} of metal.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true but R is false

A is false but R is true

⇒ An RL impedance function is to be synthesised in second Foster form. The proper function to be expanded is

Z(

*s*)

*s*Z(

*s*)

1/Z(

*s*)

Z(

*s*)/

*s*

⇒ A memoryless source emits

*n*symbols each with a probability

*p*. The entropy of the source as a function of

*n*

increases as log

*n*

decreases as log (1/

*n*)

increases as

*n*

increases as

*n*log

*n*

⇒ TM

_{01}mode in circular waveguide is analogous to

TM

_{10}mode in square waveguide

TM

_{11}mode in square waveguide

TM

_{20}mode in square waveguide

TM

_{02}mode in square waveguide

⇒ The characteristic equation for the next state (Q

_{n+1}) of a J-K flip-flop is

Q

_{n+1}= JQ

_{n}+ KQ

_{n}

Q

_{n+1}= JQ

_{n}+ KQ

_{n}

Q

_{n+1}= JQ

_{n}+ KQ

_{n}

Q

_{n+1}= JQ

_{n}+ KQ

_{n}

⇒

Match the following:

List I | List II | ||
---|---|---|---|

A. | CTFS | 1. | Periodic |

B. | DTFS | 2. | Non-periodic |

C. | CTFT | ||

D. | DTFT |

A-2, B-1, C-2, D-2

A-2, B-1, C-2, D-1

A-1, B-2, C-2, D-2

A-1, B-2, C-2, D-1

⇒ In a good voltage amplifier, its input impedance

must be high compared to the resistance of the source

must be low compared to the resistance of the source

must be equal to the resistance of the source

must be half the resistance of the source

⇒ A voltage

*v*= 100 sin (100 p

*t*+ 45°) V is applied to an impedance 10 +

*j*10 ohm. The current is

10 ∠45° A

7.07 ∠45° A

5 ∠45° A

5 ∠0 A

⇒ A meter has a resistance of 1 Ω and full scale deflection current of 1 mA. To convert into an ammeter of 1 A range, the shunt resistance should be

1000 Ω

1 Ω

0.01 Ω

0.001 Ω

⇒ The residual resistivity of a binary alloy at 0°K is

the sum of the residual resistivities of the component metals

the difference of the residual resistivities of the component metals

the product of the residual resistivities of the component metals

depend on the concentration of the minor component in the alloy

⇒ The depth of penetration at 4 MHz is 10 cm, then at 2.5 MHz it is

62.5 cm

13 cm

6.25 cm

8 cm

⇒ Thevenin's equivalent circuit

can be drawn only in time domain

can be drawn only in frequency domain

can be drawn both in time and frequency domain

can be drawn in frequency domain with some restrictions

⇒ Frequency modulation consists in

varying the frequency and amplitude of the carrier in accordance with the instantaneous value of modulating signal

varying the amplitude of the carrier in accordance with the instantaneous value of the modulating voltage

varying the frequency of the carrier voltage in accordance with the instantaneous value of the modulating voltage

vary the frequency of the carrier voltage

⇒ In a series R-L circuit when excited by a 1 volt battery the current is 1 -

*e*

^{-t}. If it is excited by a source 2 sin

*t*, the current will be

2 sin (

*t*- 45°) +

*e*

^{-t}

2 sin (

*t*+ 45°) +

*e*

^{-t}

sin (

*t*- 45°) +

*e*

^{-t}

sin (

*t*+ 45°) +

*e*

^{-t}

⇒ Radiation intensity does not depend upon

the antenna direction

antenna width

both (a) and (b)

none of the above

⇒ In the circuit of figure for sinusoidal input the waveform of the output will be as show

figure A

figure B

figure C

figure D

⇒ In figure what is the base current if V

_{BE}= 0

10 mA

9.3 mA

10 μA

9.3 μA

⇒ Microwave signals follow the curvature of the earth and the phenomenon is known as

tropospheric scatter

duct propagation

Faraday effect

none of the above

⇒ If the bandwidth is increased by 2, the γ

_{FM}γ

_{AM}(where γ is the ratio of SNR of output to SNR at input, FM is frequency modulation and AM is amplitude modulation) is increased by a factor of

2

3

4

6

⇒ In the above case the hexadecimal notation for the last memory location is

0

FFFF

3FFF

5FFF

⇒

**Assertion (A):** A radiation pyrometer is very suitable for high temperature measurement.

**Reason (R):** When temperature is high, a physical contact between hot body and thermometer is not desirable.

Both A and R are true and R is correct explanation of A

Both A and R are true but R is not correct explanation of A

A is true R is false

A is false R is true

⇒ For K map of the given figure the simplified Boolean expressio

Y = A B C + A B C + A B C

Y = A C + B

Y = A B C + ABC

Y = A B C + AB C + ABC

⇒

**Assertion (A):** Millman's theorem helps in replacing a number of current sources in parallel by a single current source.

**Reason (R):** Maximum power transfer theorem is applicable only for dc, circuits.

Both A and R are true and R is correct explanation of A

Both A and R are true and R is not the correct explanation of A

A is true but R is false

A is false but R is true