Question is ⇒ A flip flop is a, Options are ⇒ (A) combinational circuit, (B) memory element, (C) arithmetic element, (D) memory or arithmetic element, (E) , Leave your comments or Download question paper.

Question is ⇒ A flip flop is a, Options are ⇒ (A) combinational circuit, (B) memory element, (C) arithmetic element, (D) memory or arithmetic element, (E) , Leave your comments or Download question paper. Previous question Next question


Q1.	A flip flop is a
A.	combinational circuit [Wrong Answer]
B.	memory element [Correct Answer]
C.	arithmetic element [Wrong Answer]
D.	memory or arithmetic element [Wrong Answer]
View Answer 1 -1 Explanation:- Answer : B Discuss it below : !! OOPS Login [Click here] is required to post your answer/result Help other students, write article, leave your comments

Previous question Next question

Also Read Similar Questions Below :

⇒ In the circuit of figure the current through 5 Ω resistance at t = &infin
0
0.416666666666667
6.67 A
5.1 A

⇒ In the following figure C = 0.02 μF, and V_th is known to be of frequency ω = 10⁷ rad/sec and r_d = 2.5 Ω and Z_Th = R_Th = 10 Ω Then phase angle between i_d and V_{d26.5°
25°
30°
0°}

⇒ In a pneumatic bellows
the input surface, output surface and side walls are corrugated
the input surface and output surface are flat but the side walls are corrugated
the input surface and side walls are flat but the output surface is corrugated
the input surface and output surface are corrugated but the side walls are flat

⇒ Assuming accumulator contain A 64 and the carry is set (1). What will register A and carry (CY) contain after ORA A?
A 6 H, 1
A 6 H, 0
00 H, 0
00 H, 1

⇒ For a sinusoidal input, the circuit shown in the figure will act
Pulse generator
Full wave rectifier
Ramp generator
Voltage Doubler

⇒ Presently, the worlds's largest and most advanced multi-purpose communication satellite is
INSAT-2
Intelsat-V
INSAT-ID
Olympus-I

⇒ The resolution of a DAC depends on which of the following?
The number of bits
Monotonicity
Reference voltage
The values of resistance

⇒ The polar plot of G(jω) = 1/jω is
positive imaginary axis
positive real axis
negative imaginary axis
negative real axis

⇒ For a random variable x following the probability density function, p(x), shown in figure, the mean and the variance are respective
1/2 and 2/3
1 and 4/3
1 and 2/3
2 and 4/3

⇒ If an electron move through a potential difference of 500 V, the energy possesses by it will be
500 ergs
500 joules
500 eV
500 mV

⇒ The signals in 8086 are in maximum mode when
MN / MX pin is tied to V_cc
MN / MX Pin is grounded
MN / Mx pin is left open
none of the above

⇒

Assertion (A): Decoder is not a combinational circuit.

Reason (R): Every memory element of semi conductor form has a decoder.

Both A and R are correct and R is correct explanation of A
Both A and R are correct but R is not correct explanation of A
A is true, R is false
A is false, R is true

⇒ A 1000 kHz carrier wave modulated 40% at 40000 Hz is applied to a resonant circuit tuned to a carrier frequency and having Q = 140. What is the degree of modulator after transmission through the circuit?
0.4
0.2
0.27
0.54

⇒ The statement IMPLICIT INTEGER (A - F) in FORTRAN identifies
all variable names which begin with A, B, C, D, E or F as being of integer type
all character names which begin with A, B, C, D, E, or F as being of integer type
all variable names which begin with A and have 6 characters
none of the above

⇒ The active elements on the positive and negative plates of lead acid battery are:
lead peroxide and lead
lead and lead peroxide
lead peroxide and lead sulphate
lead and lead

⇒ Decimal 18.29 when converted int 10's complement will become
81.7707
81.7
81.777
81.077

⇒

Assertion (A): CRO can be used to study waveshape accurately.

Reason (R): Input impedance of a CRO is very high.

Both A and R are true and R is correct explanation of A
Both A and R are true but R is not correct explanation of A
A is true R is false
A is false R is true

⇒

Match the following:

	List I		List II
A.	Detection of a periodic signal in noise	1.	Increase in bandwidth
B.	Recovery of a band limited signal from its uniformly sampled values	2.	Slope overload error
C.	Finer quantization of signal	3.	Nyquist rate
D.	Delta modulation	4.	Cross correlation

A-4, B-3, C-1, D-2
A-3, B-4, C-2, D-1
A-4, B-3, C-2, D-1
A-4, B-2, C-1, D-3

⇒ Which of the following is not a key word in C?
pop
for
if
union

⇒ A pulse train can be delayed by a finite number of clock periods by using
serial in-serial out shift register
parallel in serial out shift register
serial in-parallel out shift register
parallel in parallel out shift register

⇒ The noise figure is
3 dB
6 dB
6.6 dB
12 dB

⇒ If V_in is 0.99 V, what is the digital output of the ADC 0801 after INTER goes low?
0011 0011
0101 1111
0111 1100
1111 1111

⇒ The complicated shapes in the polar plots are only due to time constants in the numerator of transfer functions.
TRUE
FALSE

⇒ The zinc can of a dry cell serves as positive terminal.
TRUE
FALSE

⇒ Parallel adder is
sequential circuit
combinational circuit
either sequential or combinational circuit
none of the above

⇒ - 56 is not a valid real constant in Fortran.
TRUE
FALSE

⇒ The main systems used for generation of SSB are
filter method
phase cancellation method
third method
all of the above

⇒ As temperature increases
the forbidden energy gap in silicon and germanium increase
the forbidden energy gap in silicon and germanium decrease
the forbidden energy gap in silicon decreases while that in germanium decreases
the forbidden energy gap in silicon increases while that in germanium decreases

⇒ At FM demodulator output noise power density
increases with frequency
decreases with frequency
remains unaltered
none of the above

⇒ Which one of the following statements regarding compandor is FALSE?
It compresses the higher-amplitude parts of a signal before modulation and expands them back to normal again after demodulation.
It gives preferential treatment to the weaker parts of the signal
For weaker signals it gives a poor ratio of signal strength to quantizing error
Weaker signals, traverse more quantum steps than they would do otherwise and so quantizing error is reduced.