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Q1. | A digital clock uses __________ chip |

A. | SSI [Wrong Answer] |

B. | LSI [Correct Answer] |

C. | VLSI [Wrong Answer] |

D. | MSI [Wrong Answer] |

View Answer
Explanation:-
Answer : BDiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒ The magnetic quantum number determines the component of angular momentum along a prescribed direction.

TRUE

FALSE

⇒ The emission of light is LED due to

emission of holes

emission of electrons

generation of electromagnetic radiations

conversion of heat energy into illumination

⇒ The noise margin of a TTL gate is about

0.2 V

0.4 V

0.6 V

0.8 V

⇒ Which of the following real variable names is not valid in Fortran?

BETA

ALPHA

A

AB * 2

⇒ Poynting vector signifies which of the following?

Power density vector producing electrostatic field

Power density vector producing electromagnetic field

Current density vector producing electrostatic field

Current density vector producing electromagnetic field

⇒ The eigen values of a skew symmetric matrix are

always zero

always pure imaginary

either zero or pure imaginary

always real

⇒ If the voltage across the last resistor is V, and all the resistor is unity. Then V

_{s}is give

8 V

4 V

13 V

0

⇒ Which of the following represents a stable system?

- Impulse response decreases exponentially.
- Area within the impulse response in finite.
- Eigen values of the system are positive and real.
- Roots of the characteristic equation of the system are real and positive.

1 and 4

1 and 3

2, 3 and 4

1, 2

⇒

**Assertion (A):** C has 32 keywords like auto, if, do, float etc.

**Reason (R):** Key words can not be used as variable names in C.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct R is wrong

A is wrong R is correct

⇒ In TV broadcast, UHF range is

606 - 790 MHz

100 - 150 MHz

41 - 68 MHz

174 - 230 MHz

⇒ A λ/8 section of transmission line is determined of load impedance of (2 -

*j*5) Ω. If characteristic impedance of line is 10 Ω. Then input impedance of line is

10 Ω

(6.9 +

*j*7.24) Ω

(1.75 +

*j*3.098) Ω

(2 -

*j*5) Ω

⇒ A

*n*-type silicon sample contains a donor concentration of N

_{d}= 2 x 10

^{16}cm

^{-3}. The minority carrier hole lifetime is t

_{p0}= 5 μs. The thermal equilibrium generation rate of hole is:

1.125 x 10

^{9}cm

^{-3}s

^{-1}

0.625 x 10

^{9}cm

^{-3}s

^{-1}

4.5 x 10

^{9}cm

^{-3}s

^{-1}

2.25 x 10

^{9}cm

^{-3}s

^{-1}

⇒ In the sale of diamonds the unit of weight is carat. One carat is equal to

100 mg

150 mg

200 mg

500 mg

⇒ Two port Z parameter not exist for the circuit if

Δ

*z*= 0

Δ

*z*

Δ

*z*= 1

always exist

⇒ Wave A starts its positive half cycle at ω

*t*= 30° and wave B starts its positive half cycle at ω

*t*= 75° then wave B is leading wave A by 45°.

TRUE

FALSE

⇒ The velocity of electromagnetic wave in a good conductor is

3 x 10

^{8}m/s

more than 3 x 10

^{8}m/s

very low

high

⇒ Two wires A and B have the same cross-section area and are made of the same material. R

_{A}= 600 Ω and R

_{B}= 100 Ω. The number of times A is longer than B is

6

2

4

5

⇒ In a network

Number of links = Number of branches - number of nodes + 1

Number of links = Number of branches - number of nodes

Number of links = Number of branches - number of nodes - 1

Number of links = Number of branches - number of nodes - 2

⇒ The type of feedback in the following circuit diag

Voltage shunt

Current-shunt

Voltage series

Current series

⇒ The radio horizon for space waves is about three-fourth as for as the optical horizon.

TRUE

FALSE

⇒

**Assertion (A):** When performance specifications are given in term of transient response characteristics, root locus method is a suitable method.

**Reason (R):** When performance specifications in terms of state variables are given, modern control methods can be used.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct but R is wrong

R is correct but A is wrong

⇒ In

*h*parameter representation, the independent variables are

I

_{1}and V

_{2}

I

_{2}and V

_{1}

V

_{1}and V

_{2}

I

_{1}and I

_{2}

⇒ Find the Fourier transform of the half cosine pulse as shown bel

0.5 {sin

*c*[0.25(

*f*- 1)] + sin

*c*[2.5(

*f*+ 1)]}

0.5 {sin

*c*[0.5(

*f*- 1)] + sin

*c*[0.5(

*f*+ 1)]}

0.25 {sin

*c*[0.25(

*f*- 1)] + sin

*c*[0.25 (

*f*- 1)]}

0.25 {sin

*c*[0.5(

*f*- 1)] + sin

*c*[0.5(

*f*- 1)]}

⇒ Consider the expression

*b*=

*acd*(

*xz*). The correct C statement for above expression is

*a c d*(

*x**

*z*)

*a**

*c**

*d** (

*x z*)

*a**

*c**

*d*(

*x**

*z*)

None of the above

⇒ Negative feedback is used in audio amplifiers to

operate class C

reduce distortion

increase distortion

increase gain

⇒ In a driving point function poles and zeros must be conjugate if complex or imaginary.

TRUE

FALSE

⇒ The capacitance of a parallel plate capacitor varies as per the equation C(

*t*) = C

_{0}(1 - cos ω

*t*). It is connected to a battery of V volts. The equation for current is

ωC

_{0}V (1 - cos ω

*t*)

ωC

_{0}V(1 - sin ω

*t*)

ωC

_{0}V (1 - sin 2ω

*t*)

ωC

_{0}V sin ω

*t*

⇒ E

_{G}for silicon is 1.12 eV and that for germanium is 0.72 eV. Therefore it can be concluded that

more number of electron-hole pairs will be generated in silicon than in germanium at room temperature

less number of electron hole pairs will be generated in silicon than in germanium at room temperature

equal number of electron-hole pairs will be generated in both at lower temperatures

equal number of electron-hole pairs will be generated in both at higher temperatures

⇒ A sample of N type semiconductor has an electron density of 6.25 x 10

^{18}/cm

^{3}at 300 K. If intrinsic concentration of carriers in this sample is 2.5 x 10

^{13}/cm

^{3}at this temperature, the hole density is

10

^{6}/ cm

^{3}

10

^{8}/ cm

^{3}

10

^{10}/ cm

^{3}

10

^{12}/ cm

^{3}

⇒ For dielectrics in alternating field, polarizability a

_{e}is a complex quantity. The imaginary part of a

_{e}is zero for

ω = 0

ω → ∞

ω = 0 and ω → ∞

ω = natural frequency ω

_{0}