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Q1. | A circular sphere mile is the area of cross-section of a wire |

A. | having a diameter equal to 1 miles [Correct Answer] |

B. | having a radius equal to 1 miles [Wrong Answer] |

C. | having a circumference equal to 1 miles [Wrong Answer] |

D. | none of the above [Wrong Answer] |

View Answer
Explanation:-
Answer : ADiscuss it below :!! OOPS Login [Click here] is required to post your answer/resultHelp other students, write article, leave your comments |

**Also Read Similar Questions Below :**

⇒

Match the following:

List I (Double Rectifier) | List II (Number of Diodes) | ||
---|---|---|---|

A. | Full wave Bridge rectifier | 1. | 1 |

B. | Half wave rectifier | 2. | 2 |

C. | Full wave rectifier using centre tapped transformer | 3. | 4 |

A-1, B-2, C-3

A-3, B-1, C-2

A-2, B-1, C-3

A-3, B-1, C-2

⇒ Which of the following theorems enables a number of voltage (or current) sources to be combined directly into a single voltage (or current) source?

Superposition theorem

Compensation theorem

Millman's theorem

Thevenin's theorem

⇒ What is the propagation constant for air filled wave guide with dimensions

*a*= 1.59" and

*b*= 0.795" at 4.95 GHz. The wave impedance is

400.94 Ω

562.94 Ω

502.80 Ω

492.80 Ω

⇒

**Assertion (A):** The velocity factor of a line is the ratio of wave velocity on the line to speed of light.

**Reason (R):** If the conductors of a line are immersed in a non magnetic insulating liquid, the wave velocity increases.

Both A and R are correct and R is correct explanation of A

Both A and R are correct but R is not correct explanation of A

A is correct but R is wrong

A is wrong but R is correct

⇒ In a bridge inverter with single pulse width modulation

the output frequency is equal to frequency of reference signal

the output frequency is equal to frequency of control signal

either (a) or (b)

neither (a) nor (b)

⇒ A linear system is characterized by H(ω) = B

*e*

^{-2ω2}the system is physically

unrealizable

realizable

depends upon B

depends upon constant 2

⇒ A variable reluctance type tachometer has 150 teeth on rotor. The counter records 13500 pulse/sec. The rotational speed is

4800 RPM

5400 RPM

6000 RPM

7200 RPM

⇒ The addressing mode depicted in the given figur

direct

register

register indirect

implicit

⇒ McMurray Bedford full bridge inverter uses

natural commutation

auxiliary commutation

complementary commutation

any of the above

⇒ The changes in ambient temperature affect the open loop gain of amplifier.

TRUE

FALSE

⇒ For a current transformer, the standard secondary rating is

1 A or 5 A

2.5 A

0.416666666666667

5 A or 10 A

⇒ What will be minimum conversion rate in 6 bit dual slope A/D converter uses a reference of -6v and a 1 MHz clock. It uses a fixed count of 40 (101000).

9000

9259

1000

1000

⇒ For any given two port network, any parameter set can be determined from measurements made at the two ports.

TRUE

FALSE

⇒ A full adder is to be implemented using half adders and OR gates. A 4 bit parallel adder without any initial carry requires

8 half adders and 4 OR gates

8 half adders and 3 OR gates

7 half adders and 3 OR gates

7 half adders and 4 OR gates

⇒ Which of the following noise becomes of great importance at high frequencies?

Shot noise

Agitation noise

Flicker noise

Transit time noise

⇒ The reverse saturation current depends on the reverse bias.

TRUE

FALSE

⇒ In a R-L-C circuit at resonance is

maximum in series resonance and minimum in parallel resonance.

maximum in parallel resonance and minimum in series resonance

minimum in both series and parallel resonances

maximum in both series and parallel resonances.

⇒ Generally the wall thickness of rectangular waveguide is

about 1-5 mils

about 40-100 mils

about 0.1 to 0.5 mils

about 500 mils

⇒ A feedback network to be used with an amplifier to provide oscillation is tested and found to give an output of 0.124 V with a 0.5 V input. What percentage negative feedback should be introduced to the amplifier so that linear oscillations result?

0.0125

0.025

-0.0125

-0.025

⇒ In an FM signal, the power

increases as the modulation index increases

reduces as the modulation index increase

increases as the modulation index decreases

remains constant when the modulation index increases

⇒ In FM, the frequency deviation is

always constant

directly proportional to modulating frequency

inversely proportional to modulating frequency

proportional to amplitude of modulating signal

⇒ Consider a control system shown in given figure. For slight variation in G, the ratio of open loop sensitivity to closed loop sensitivity will be give

1 : (1 + GH)

1 : (1 + GH)

^{- 1}

1 : (1 - GH)

1 : (1 - GH)

^{- 1}

⇒ Divergence of curl A is

∇ . (∇ x A) = 1

∇ . (∇ x A) = 0

∇ . (∇ x A) = ∇

∇ . (∇ x A) = - ∞

⇒ What will be conversion time of a successive approximation A/D converter which uses 2 MHz clock and 5 bit binary ladder containing 8 V reference.?

2.5 μ sec

25 μ sec

3 μ sec

4 μ sec

⇒ In a CD player the speed of CD is

constant at 500 rpm

constant at 200 rpm

varies from 200 to 500 rpm

none of the above

⇒ The voltage transfer functions of two port circuits connected in cascade can be easily found from

product of individual ABCD matrices

product of voltage transfer functions of two networks

sum of

*z*matrices

sum of

*h*matrices

⇒ The impedance of a coil above self-resonant frequency is

inductive

capacitive

resistive

none

⇒ If reference sound pressure P

_{0}is 2 x 10

^{-5}N/m

^{2}, a sound pressure of 90 dB is equal to

0.632 N/m

^{2}

0.707 N/m

^{2}

0.835 N/m

^{2}

0.925 N/m

^{2}

⇒ For a npn BJT transistor

*f*is 1.64 x 10

_{β}^{8}H

*z*. C

_{μ}= 10

^{-14}F; C

_{p}= 4 x 10

^{-13}F and DC current gain is 90. Find

*f*and

_{T}*g*(

_{m}*f*= cut off frequency, C

_{β}_{μ}= capacitance, C

_{p}= parasitic capacitance,

*g*= transconductance,

_{m}*f*= gain BW product)

_{T}*f*= 1.47 x 10

_{T}^{10}H

*z*;

*g*= 38 milli mho

_{m}*f*= 1.64 x 10

_{T}^{8}H

*z*;

*g*= 30 milli mho

_{m}*f*= 1.47 x 10

_{T}^{9}H

*z*;

*g*= 38 mho

_{m}*f*= 1.33 x 10

_{T}^{12}H

*z*;

*g*= 0.37 m-mho

_{m}⇒ Let

*f*

_{1}(

*t*) = G

_{1}(

*t*) + 4,

*f*

_{2}(

*t*) = G

_{2}(

*t*) + 3. If G

_{1}(

*t*) and G

_{2}(

*t*) are uncorrected then the correlation between

*f*

_{1}(

*t*) and

*f*

_{2}(

*t*) are

12

7

6

zero