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In a totally irreversible isothermal expansion process for an ideal gas, ΔE = 0, ΔH = 0. Then ΔQ and ΔS will be | |
A. | ΔQ = 0, ΔS=0 [Wrong Answer] |
B. | ΔQ = 0 , ΔS = +ve [Correct Answer] |
C. | ΔQ = 0, ΔS = -ve [Wrong Answer] |
D. | ΔQ = +ve , ΔS= +ve [Wrong Answer] |